C++ Primer 读书笔记 - 第十四章
添加时间:2013-6-2 点击量:
1. An overloaded operator must have at least one operand of class or enumeration type.
2. Default arguments for overloaded operators are illegal, except for operator(), the function-call operator.
3. The assignment (=), subscript ([]), call (()), and member access arrow (->) operators must be defined as members. Defining any of these operators as a nonmember function is flagged at compile time as an error.
Like assignment, the compound-assignment operators ordinarily ought to be members of the class. Unlike assignment, they are not required to be so and the compiler will not complain if a nonmember compound-assignment operator is defined.
Other operators that change he state of their object or that are closely tied to their given type - such as increment, decrement, and dereference - usually should be members of the class.
Symmetric operators, such as the arithmetic, equality, relational, and bitwise operators, are best defined as ordinary nonmember functions.
4. < 和 == 的定义应当对峙一致。
5. 定义下标操纵的类,应当有两个版本:返回引用的非const成员,返回const引用的const成员。
6. 不消为ScreenPtr类定义默认机关函数,是以,一个ScreenPtr对象将老是指向一个Screen对象,不会有未绑定的ScreenPtr,这一点和内置指针不合。
6. Function Object
class GT_cls {
public:
GT_cls(size_t val = 0) : bound(val) { }
bool operator() (const string &s) { return s.size() >= bound; }
private:
std::string::size_type bound;
};
count_if(words.begin(), words.end(), GT_cls(6));
count_if的原型是
template <class InputIterator, class UnaryPredicate>
typename iterator_traits<InputIterator>::difference_type
count (InputIterator first, InputIterator last, UnaryPredicate pred)
{
typename iterator_traits<InputIterator>::difference_type ret = 0;
while (first!=last) {
if (pred(first)) ++ret;
++first;
}
return ret;
}
因为类重载了()操纵符,所以pred(first)仍然可用。
文艺不是炫耀,不是花哨空洞的文字堆砌,不是一张又一张的逆光照片,不是将旅行的意义转化为名牌包和明信片的物质展示;很多时候它甚至完全不美——它嘶吼、扭曲,它会痛苦地抽搐,它常常无言地沉默。——艾小柯《文艺是一种信仰》
1. An overloaded operator must have at least one operand of class or enumeration type.
2. Default arguments for overloaded operators are illegal, except for operator(), the function-call operator.
3. The assignment (=), subscript ([]), call (()), and member access arrow (->) operators must be defined as members. Defining any of these operators as a nonmember function is flagged at compile time as an error.
Like assignment, the compound-assignment operators ordinarily ought to be members of the class. Unlike assignment, they are not required to be so and the compiler will not complain if a nonmember compound-assignment operator is defined.
Other operators that change he state of their object or that are closely tied to their given type - such as increment, decrement, and dereference - usually should be members of the class.
Symmetric operators, such as the arithmetic, equality, relational, and bitwise operators, are best defined as ordinary nonmember functions.
4. < 和 == 的定义应当对峙一致。
5. 定义下标操纵的类,应当有两个版本:返回引用的非const成员,返回const引用的const成员。
6. 不消为ScreenPtr类定义默认机关函数,是以,一个ScreenPtr对象将老是指向一个Screen对象,不会有未绑定的ScreenPtr,这一点和内置指针不合。
6. Function Object
class GT_cls {
public:
GT_cls(size_t val = 0) : bound(val) { }
bool operator() (const string &s) { return s.size() >= bound; }
private:
std::string::size_type bound;
};
count_if(words.begin(), words.end(), GT_cls(6));
count_if的原型是
template <class InputIterator, class UnaryPredicate>
typename iterator_traits<InputIterator>::difference_type
count (InputIterator first, InputIterator last, UnaryPredicate pred)
{
typename iterator_traits<InputIterator>::difference_type ret = 0;
while (first!=last) {
if (pred(first)) ++ret;
++first;
}
return ret;
}
因为类重载了()操纵符,所以pred(first)仍然可用。
文艺不是炫耀,不是花哨空洞的文字堆砌,不是一张又一张的逆光照片,不是将旅行的意义转化为名牌包和明信片的物质展示;很多时候它甚至完全不美——它嘶吼、扭曲,它会痛苦地抽搐,它常常无言地沉默。——艾小柯《文艺是一种信仰》